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Physics 14 Online
OpenStudy (anonymous):

What is the clockwise torque on the following lever? https://saintjamesfl.ignitiaschools.com/media/g_ipc_2014/12/ipcu12t02d_q8.gif 5.0 Nm 125 Nm 250 Nm 0.0 Nm

OpenStudy (anonymous):

@Wolverine32 would you help me please?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

im geting 240 let me try something else hold on

OpenStudy (anonymous):

OK :)

OpenStudy (anonymous):

man this hard sorry im stuck i want to guess 5.0 or 250 but i dont know ask someone dont wna u to get it wrong

OpenStudy (anonymous):

Np thanks :)

OpenStudy (vincent-lyon.fr):

I'm afraid and the answers are wrong.

OpenStudy (anonymous):

if it is asking for the clockwise torque only it should be the one you get using \(F=25N\) applied at \(5m\) of the pivot, so it gives: \(25N\times 5m =125Nm\)

OpenStudy (vincent-lyon.fr):

Now I understand, Thanks @Greg_D :)) I assumed the question was "What is the clockwise NET torque on the following lever?" (ie: counting clockwise as positive) Now, @LmL, if you have understood Greg's answer, you should be able to answer these new questions: - What is the anti-clockwise torque on the lever? - What is the net torque on the lever?

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