please helpppppppp...... medals and fan question in comments
@Michele_Laino help me once again
British curriculum?
what ?
please wait, I'm working on your question...
okay...
here is my reasoning: |dw:1434709278703:dw| we have: \[\Large L = 2r\sin x\]
thank you...
now, using the theorem of Pitagora, we can write: \[\begin{gathered} \sqrt {4{r^2} - A{B^2}} = 2r\sin x \hfill \\ \sqrt {4{r^2} - A{B^2}} = 2r\sqrt {1 - {{\left( {\cos x} \right)}^2}} \hfill \\ 2r\sqrt {1 - {{\left( {\frac{{AB}}{{2r}}} \right)}^2}} = 2r\sqrt {1 - {{\left( {\cos x} \right)}^2}} \hfill \\ \end{gathered} \]
\[\Large \begin{gathered} \sqrt {4{r^2} - A{B^2}} = 2r\sin x \hfill \\ \sqrt {4{r^2} - A{B^2}} = 2r\sqrt {1 - {{\left( {\cos x} \right)}^2}} \hfill \\ 2r\sqrt {1 - {{\left( {\frac{{AB}}{{2r}}} \right)}^2}} = 2r\sqrt {1 - {{\left( {\cos x} \right)}^2}} \hfill \\ \end{gathered} \]
so, by comparison, we can write: \[\large \cos x = \frac{{AB}}{{2r}}\]
now, using the condition of your problem, we can write: \[\large \begin{gathered} AB + AC + arc(BC) = \pi r \hfill \\ 2AB + 2xAB = \pi r \hfill \\ 2AB\left( {1 + x} \right) = \pi r \hfill \\ AB = \frac{{\pi r}}{{2\left( {1 + x} \right)}} \hfill \\ \end{gathered} \] since, by definition of radians we can write: \[\large arc(BC) = 2xAB\]
now substitute the value of AB, into the expression for cos x, what do you get?
brilliant!
thanks!! :) @alekos
thanks @Michele_Laino
:) @yajna
it all follows through quite nicely. how the hell you came up with that so quickly astounds me
@Michele_Laino is a genius @alekos
btw @yajna this is the hardest question of this type you can hope to find in p3. So don't stress yourself too much if you find it hard the first time.
A true genius she is! @Michele_Laino :)
yes...
thanks! @Miracrown
@michele what do you do for a living?
at the moment I have no job!
you've got to be kidding! what sort of job are you looking for?
for example teacher, draftsman or translator from English to Italian. my last job was to translate texts of patents
from English to Italian
and my preceding job was nautical draughtsman
have you been out of work for long?
at the moment I am without job from at least 10 months!
i am sure you will find another job soon. keep looking and it will happen. you're a smart lady and you deserve it.
Thanks for your encouragement!! :) nevertheless, please keep in mind that I'm a male, Lol!!
Join our real-time social learning platform and learn together with your friends!