How does changing the function from f(x) = −5 cos 2x to g(x) = −5 cos 2x − 3 affect the range of the function? The function shifts down 3 units, so the range changes from −1 to 1 in f(x) to −4 to −2 in g(x). The function shifts down 3 units, so the range changes from −5 to 5 in f(x) to −8 to 2 in g(x). The function shifts down 5 units, so the range changes from −1 to 1 in f(x) to −6 to −4 in g(x). The function shifts down 5 units, so the range changes from −5 to 5 in f(x) to −10 to 0 in g(x).
@phi @radar @aloud @AutumnRoseT @xavierbo2 @Data_LG2 @mathmate @HWBUSTER00 @hartnn
was up
help mee?
i really d know
okay thanks though
@mathmate ?
@georgia545 @aloud Do you know the range of f(x)?
0??
|dw:1434724687580:dw|
So the range of y=cos(x) is [-1,1] Are you familiar with the interval notation?
noo
Check this out: http://www.coolmath.com/algebra/07-solving-inequalities/03-interval-notation-01
oh yeah i do i just didnt know that was the name
range of y=[-1,1] means the range of y can take any value between -1 and +1.
Multiplying y by -5 means stretching the function vertically and flipping it about the x-axis. so y=-5cos(x) has a shape like this: |dw:1434724951272:dw| so what is the range of y=-5cos(x)?
Join our real-time social learning platform and learn together with your friends!