Question

Y=3-logx
How is this done??

Answer 1

Is that \[y = \log_3(x)\]?


use the log identity

\[y = \log_b(x)\qquad\iff\qquad b^y=x \]

Answer 2

Yeah I know that but how is it done with a negative between 3 and logx

Answer 3

the answer is y=10^3-y but how

Answer 4

oh it is a negative?


like this
\[y = 3-\log(x)\]?

Answer 5

sorry for my earlier misinterpretation.

Answer 6

No its suppose to be a negative between the three and y

Answer 7

oh , right i erred

\[y = 3 - \log (x)\\
\log(x) = 3-y\\
x = 10^{3-y}\]

Answer 8

Is this what you were looking for?

Answer 9

Wait so what exactly did you do?

Answer 10

\[y = 3 - \log (x)\]add log x to both sides of the equation, \[y+\log(x) = 3\]take away y from both sides .\[\log(x) = 3-y\]then applied log identity \[x = 10^{3-y}\]

Answer 11

No I think I got it now! Thank you!