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OpenStudy (starwars18):
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.
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OpenStudy (starwars18):
\[\frac{ \sin x }{ 1 - \cos x } + \frac{ \sin x }{ 1 + \cos x } = 2 \csc x\]
OpenStudy (dan815):
okay first thing to know is csc(x) = 1/sin(x)
OpenStudy (starwars18):
yes
OpenStudy (dan815):
you should simplify the left side, by multiplying both fracctions by the conjugate
OpenStudy (dan815):
1-cos(x) and 1+cos(x) are factors of 1-(cos(x))^2
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OpenStudy (dan815):
and 1-cos^2(x) = sin^2(x)
as sin^2(x) + cos^2(x) = 1
this identity comes from the unit circle
OpenStudy (dan815):
okay yep it is right 2/sin(x) = 2csc(x) should be the right answer
OpenStudy (starwars18):
so sin x * (1 + cos x) + sin^3 x
OpenStudy (starwars18):
so they all cancel out leaving 2 over sin x... i get it now
OpenStudy (anonymous):
2 / sin(x) is like saying 2 times 1 /sin(x) which mean 2 times csc(x) or 2 csc(x) since csc = 1/sin(x)
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OpenStudy (starwars18):
yes, ty i got it. sorry i forgot to close the question!!!
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