Question

A wooded area in a state park has a mixture of different types of trees. There are 800 pine trees and 50 oak trees. The number of pine trees is decreasing at a rate of 5% per year. The number of oak trees is increasing at a rate of 15% per year. If these trends continue:

Write two functions to model this situation, and graph those two functions on the same coordinate grid.
During what year in the future will the park have approximately the same number of pine and oak trees?

Answer 1

@musicmaster @rockstar0765 @darkb0nebeauty @TheGaMer007 @nuccioreggie can yall answer A and b FOR ME PLEASE , ILL GIVE BEST ANSWER, FRIEND. AND TESTIMONIAL @sleepyjess @sammixboo @dan815

Answer 2

@radar @tywower

Answer 3

@peachpi

Answer 4

the formula for number of pines after n years is
N = 800( 1- 0.050)^n

Answer 5

can you work out what it would be for the oaks?

Answer 6

ummm idk, ill tyr

Answer 7

try

Answer 8

14% = 0.14

Answer 9

wats that for?
( the .14)?

Answer 10

look at the function for the pines
the 0.05 come from the 5%
this time its 0.14 but the number of trees are increasing so its + 0.14

Answer 11

* OH sorry its 0.15 ( 15%)

Answer 12

N = 800( 1- 0.15)^n right?

Answer 13

no - the number is INCREASING not decreasing

Answer 14

N = 800( 1+0.15)^n

Answer 15

lol I'll do that again
N = 800(0.95)^n
and
N = 800(1.14)^n

Answer 16

- these are the same as the others but more concise

Answer 17

are those the 2 functions to the first question?

Answer 18

yes

Answer 19

ohh lol ok, thankyou. wb the second question

Answer 20

how do you think you answer the second part - when number of pines = number of oaks?

Answer 21

when that happens the value N will be the same for oaks and pines

Answer 22

is it the 14th year?

Answer 23

o nevermind sorry

Answer 24

how did you get that?

Answer 25

thats 0.15 not 0.14 my last post - i seem to have a fixation with 14!!!

Answer 26

lol ok, thankyou!

Answer 27

i've made another error for the oak trees the number is 50 not 800 so that the second function is

50(1.15)^n


sorry