Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

Can someone tell me how you factor this for a medal?

OpenStudy (anonymous):

Factor 3x^2y^2 - 2xy^2 - 8y^2

OpenStudy (anonymous):

(x+2y)(3x-4y)

OpenStudy (mrnood):

that is not correct the first expansion of that would give 3x^ as a term - but there is no such term in the expression

OpenStudy (mrnood):

@ImaGuest This is a good reason why you should not accept direct answers You have no idea of the competence of those answering - MANY answers here are just WRONG

OpenStudy (plasmataco):

lol

OpenStudy (anonymous):

I know, thats why I said "tell me how you factor...". I usually don't accept direct answers anyways :)

OpenStudy (plasmataco):

are you sure there is a 3x^2y^2?

OpenStudy (mrnood):

\[3x ^{2}y ^{2} - 2xy ^{2} - 8y ^{2}\]

OpenStudy (plasmataco):

because that is kinda complicated...

OpenStudy (plasmataco):

ohhhhh.

OpenStudy (plasmataco):

well. what do you do first?

OpenStudy (plasmataco):

there is y^2 in every term, so you can factor that out.

OpenStudy (mrnood):

To be a factor - the values have to appear in every term you can see y^2 is in every term - so start by making that a factor

OpenStudy (anonymous):

Yeah, I'm positive.

OpenStudy (plasmataco):

you will get y^2(3x^2-2x-8)

OpenStudy (plasmataco):

now. how do you factor 3x^2-2x-8?

OpenStudy (mrnood):

@Plasmataco you should let @ImaGuest do the work 0 it's his question

OpenStudy (anonymous):

@MrNood I would if I could, and if I could I wouldn't be on this site.

OpenStudy (anonymous):

I wouldn't have made this thread if I knew what to do

OpenStudy (plasmataco):

(3x+4)(x-2)

OpenStudy (plasmataco):

so, your answer would be y^2(3x+4)(x-2)

OpenStudy (anonymous):

Ok but I want to know how to factor this.

OpenStudy (plasmataco):

ok.

OpenStudy (anonymous):

A direct answer is fine, but I need to show my work

OpenStudy (plasmataco):

I know. I'll explain.

OpenStudy (anonymous):

And if you could walk me through it, I would appreciate it

OpenStudy (plasmataco):

when you factor a ax^2+bx+c,

OpenStudy (plasmataco):

waaaait. im explaining, I like to give the answer, then explain.

OpenStudy (mrnood):

you have the answer above y^2 (3x+4)(x-2) now try the next similar question

OpenStudy (mrnood):

9 out of 10 posters will leave as soon as you give th eanswer

OpenStudy (plasmataco):

when you factor, you look at a. if it's 1, you automatically get into a format of (x+?)(x+?)

OpenStudy (anonymous):

Well I didn't leave. What does that make me?

OpenStudy (plasmataco):

? wat, im talking to Mr.nood

OpenStudy (plasmataco):

understand so far?

OpenStudy (mrnood):

you didn't explain yet about taking y^2 out as a factor

OpenStudy (plasmataco):

ok. when every term has a common factor, you can bring it out.

OpenStudy (plasmataco):

say you have 2y-4, 2 is a common factor, therefore, you can say 2(y-2)

OpenStudy (plasmataco):

got it?

OpenStudy (plasmataco):

now. back to the second part...

OpenStudy (mrnood):

so what are you left with when you take y^2 from the original equation @ImaGuest ?

OpenStudy (anonymous):

Nah, Im still here. Sorry, someone was at the door.

OpenStudy (plasmataco):

its fine, look above. do you get it so far?

OpenStudy (anonymous):

Yeah, so far I do.

OpenStudy (plasmataco):

ok. whenever you factor with something like the second part, you always want to end up like (ax+b)(cx+d), a and c can be one.

OpenStudy (plasmataco):

I'll give you an example, that's the easiest way to teach you.

OpenStudy (anonymous):

Alright

OpenStudy (plasmataco):

when you factor Y^2+3Y+2, you factor into (Y+2)(Y+1).

OpenStudy (plasmataco):

notice how 1*1=1 in the first term, 1+2=3, in the middle term and 1*2=2 in the third term

OpenStudy (plasmataco):

that's how you want to factor every thing, it's like a puzzle.

OpenStudy (plasmataco):

hello?

OpenStudy (anonymous):

I'm here.

OpenStudy (plasmataco):

ok. look above.

OpenStudy (plasmataco):

see if you get it.

OpenStudy (anonymous):

Yeah, I just finished reading them literally a few seconds before you said "hello?"

OpenStudy (plasmataco):

you get it?

OpenStudy (anonymous):

Yeah I do. Thanks, you were of big help!

OpenStudy (plasmataco):

no problem.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!