Can someone tell me how you factor this for a medal?
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OpenStudy (anonymous):
Factor 3x^2y^2 - 2xy^2 - 8y^2
OpenStudy (anonymous):
(x+2y)(3x-4y)
OpenStudy (mrnood):
that is not correct
the first expansion of that would give 3x^ as a term - but there is no such term in the expression
OpenStudy (mrnood):
@ImaGuest This is a good reason why you should not accept direct answers
You have no idea of the competence of those answering - MANY answers here are just WRONG
OpenStudy (plasmataco):
lol
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OpenStudy (anonymous):
I know, thats why I said "tell me how you factor...". I usually don't accept direct answers anyways :)
OpenStudy (plasmataco):
are you sure there is a 3x^2y^2?
OpenStudy (mrnood):
\[3x ^{2}y ^{2} - 2xy ^{2} - 8y ^{2}\]
OpenStudy (plasmataco):
because that is kinda complicated...
OpenStudy (plasmataco):
ohhhhh.
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OpenStudy (plasmataco):
well. what do you do first?
OpenStudy (plasmataco):
there is y^2 in every term, so you can factor that out.
OpenStudy (mrnood):
To be a factor - the values have to appear in every term
you can see y^2 is in every term - so start by making that a factor
OpenStudy (anonymous):
Yeah, I'm positive.
OpenStudy (plasmataco):
you will get y^2(3x^2-2x-8)
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OpenStudy (plasmataco):
now. how do you factor 3x^2-2x-8?
OpenStudy (mrnood):
@Plasmataco
you should let @ImaGuest do the work 0 it's his question
OpenStudy (anonymous):
@MrNood I would if I could, and if I could I wouldn't be on this site.
OpenStudy (anonymous):
I wouldn't have made this thread if I knew what to do
OpenStudy (plasmataco):
(3x+4)(x-2)
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OpenStudy (plasmataco):
so, your answer would be y^2(3x+4)(x-2)
OpenStudy (anonymous):
Ok but I want to know how to factor this.
OpenStudy (plasmataco):
ok.
OpenStudy (anonymous):
A direct answer is fine, but I need to show my work
OpenStudy (plasmataco):
I know. I'll explain.
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OpenStudy (anonymous):
And if you could walk me through it, I would appreciate it
OpenStudy (plasmataco):
when you factor a ax^2+bx+c,
OpenStudy (plasmataco):
waaaait. im explaining, I like to give the answer, then explain.
OpenStudy (mrnood):
you have the answer above y^2 (3x+4)(x-2)
now try the next similar question
OpenStudy (mrnood):
9 out of 10 posters will leave as soon as you give th eanswer
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OpenStudy (plasmataco):
when you factor, you look at a. if it's 1, you automatically get into a format of (x+?)(x+?)
OpenStudy (anonymous):
Well I didn't leave. What does that make me?
OpenStudy (plasmataco):
? wat, im talking to Mr.nood
OpenStudy (plasmataco):
understand so far?
OpenStudy (mrnood):
you didn't explain yet about taking y^2 out as a factor
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OpenStudy (plasmataco):
ok. when every term has a common factor, you can bring it out.
OpenStudy (plasmataco):
say you have 2y-4, 2 is a common factor, therefore, you can say 2(y-2)
OpenStudy (plasmataco):
got it?
OpenStudy (plasmataco):
now. back to the second part...
OpenStudy (mrnood):
so what are you left with when you take y^2 from the original equation @ImaGuest ?
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OpenStudy (anonymous):
Nah, Im still here. Sorry, someone was at the door.
OpenStudy (plasmataco):
its fine, look above. do you get it so far?
OpenStudy (anonymous):
Yeah, so far I do.
OpenStudy (plasmataco):
ok. whenever you factor with something like the second part, you always want to end up like (ax+b)(cx+d), a and c can be one.
OpenStudy (plasmataco):
I'll give you an example, that's the easiest way to teach you.
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OpenStudy (anonymous):
Alright
OpenStudy (plasmataco):
when you factor Y^2+3Y+2, you factor into (Y+2)(Y+1).
OpenStudy (plasmataco):
notice how 1*1=1 in the first term, 1+2=3, in the middle term and 1*2=2 in the third term
OpenStudy (plasmataco):
that's how you want to factor every thing, it's like a puzzle.
OpenStudy (plasmataco):
hello?
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OpenStudy (anonymous):
I'm here.
OpenStudy (plasmataco):
ok. look above.
OpenStudy (plasmataco):
see if you get it.
OpenStudy (anonymous):
Yeah, I just finished reading them literally a few seconds before you said "hello?"
OpenStudy (plasmataco):
you get it?
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