-7x^2=-448 taking the square root and completing the square please show steps
you do not have to complete the square for this one divide both sides by \(-7\) then take the square root of both sides don't forget the \(\pm\)
\[\huge~\rm~-448\div-7=?\]
64
Yep, so now you have \(x^2 = 64\) Your next step is to take square root of both sides.
\[\huge~\rm~\sqrt{x^2}=\sqrt{64}\]
64 is 8
good and the square root of X^2 ?
x
ok so whats the answer?
8x
so the equation for it would be like the steps
Nope remeber the = sign it remains there! \[\huge~\rm~x=\pm8\]
what would be the steps
We just did it ... we need to divide both sides by -7 that way we can isolate the x \[\huge~\rm~\frac{ -7x^2=-448 }{ 7 } \] We were left with \[\huge~\rm~x^2=64\] we need to solve for x so we need to square root both of those \[\huge~\rm~\sqrt{x^2}=\sqrt{64}\]
And when we did this we ended up with... \[\huge~\rm~x=\pm8\]
understood ?
yes i think so if i turned these steps it would be the correct formulas and stuff?
Can you please rephrase that ?
i'm suppose to show my work when i turn it in so if i turn these steps in would it be the correct formula?
can you help me with one more?
._. this is correct but i expect u to be able to do the next one by yourself if it is like this...i can look over the work :)
ok well the next one is a little different x^2-10x+22=-2
do i do the same thing?
We need to get it into standered for first \[\huge~\rm~ax^2+bx+c=0\]
fill it in with the number from the equation?
x^2-10x+22=-2 we add the -2 to the - \[\huge~\rm~22-2=?\]
well -24
my mistake sorry it would be just 24
\[\huge~\rm~x^2-10x+24=0\]
what numbers multiply to make 24 but adds to make -10
4 an 6 im not sure
good -4 and -6 then (x-6) (x-4) set up 2 diffrent equations x-6=0 <---solve for x x-4=0 <----solve for x
x=6 and x=4
@pooja195
yep
and then?
thats it
o so the steps are ?
i got to go
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