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Does this have an absolute minimum? f(x)=4(x^2−1)^3, [−1,2]
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Extreme value theorem http://mathworld.wolfram.com/ExtremeValueTheorem.html in that article, when they mention "minimum" they really mean "absolute minimum" a local min is possible, but it will always have a absolute min
Right, I was able to find the absolute max. at (2,108) but I couldn't find any abs min
Ohh wait! I just found it! It's at (0,-4)
yes (0,-4) is the absolute min
Thanks so much!! Sorry, I just realized the answer!
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