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Mathematics 10 Online
OpenStudy (anonymous):

Does this have an absolute minimum? f(x)=4(x^2−1)^3, [−1,2]

jimthompson5910 (jim_thompson5910):

Extreme value theorem http://mathworld.wolfram.com/ExtremeValueTheorem.html in that article, when they mention "minimum" they really mean "absolute minimum" a local min is possible, but it will always have a absolute min

OpenStudy (anonymous):

Right, I was able to find the absolute max. at (2,108) but I couldn't find any abs min

OpenStudy (anonymous):

Ohh wait! I just found it! It's at (0,-4)

jimthompson5910 (jim_thompson5910):

yes (0,-4) is the absolute min

OpenStudy (anonymous):

Thanks so much!! Sorry, I just realized the answer!

jimthompson5910 (jim_thompson5910):

no problem

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