Question

Help pl0x

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Answer 1

\[\frac{12x^4y^3z^2w}{2xy^2}\]

Answer 2

all we need to do is use division for the numbers only and use one of the exponent rules for the variables.

\[\frac{x^a}{x^b} \rightarrow x^{a-b}\]
where x = variable
a and b = numbers

so for the numbers only we have 12/2, so what's 12 divided by 2

Answer 3

6

Answer 4

yes..

so for the variables only we noticed that only x and y are present on the numerator and denominator, so we use the exponent law to figure this part out ... so
if we let a = 4 and b = 1 from earlier

\[\frac{x^4}{x^1} \rightarrow x^{4-1}\]
we just have to subtract.. so what's 4-1 ?

Answer 5

3

Answer 6

alright

so we have \[x^3\]

Answer 7

we do the same thing for the y variable because that exists on the numerator and denominator

\[\frac{y^3}{y^2} \rightarrow y^{3-2}\]
so all we need to do is subtract.. what is 3 -2 ?

Answer 8

1

Answer 9

yes so now we have just \[y^1 \] or you can write it as y only because it's to the first power... those 3 arithmetics we've just done are only necessary for this problem because z and w aren't present in the denominator, so we just leave them alone.

Answer 10

\[6x^3yz^2w\]

Answer 11

and that's our final answer.

Answer 12

tyvm<3