Question

A large emerald with a mass of 982.7 grams was recently discovered in a mine. If the density of the emerald is 2.76grams over centimeters cubed, what is the volume? Round to the nearest hundredth when necessary and only enter numerical values, which can include a decimal point
[Fill in the Blank]

Answer 1

@Jack1 can u help me when ever u get the chance (:

Answer 2

sure
mass = 982.7 grams
Density = 2.76 g/cm^3
Volume = ?

so Density = mass per unit of volume

\(\Large D = \frac mV \)
if m = 982.7
and D = 2.76
V = ???

\(\Large D = \frac mV \)

\(\Large 2.76 = \frac {982.7}V \)

Can you solve for V from here?

Answer 3

sorry i was from my computer again but would it be 276.92??

Answer 4

no i got a different answer, how did u calculate that?

Answer 5

sorry i think i calculated it wrong

Answer 6

s'ok

\(\Large 2.76 = \frac {982.7}V\)

multiply both sides by V

\(\Large 2.76 \times V = \frac {982.7}V \times V\)

V's now cancel out on the Right Hand Side, so you left with

\(\Large 2.76 \times V = 982.7\)

now divide both sides by 2.76

\(\Large \frac {2.76 \times V}{2.76} = \frac {982.7}{2.76}\)

2.76 over 2.76 on Left Hand Side = 1

\(\Large V = \frac {982.7}{2.76}\)

so answer = ?

Answer 7

i divided and got 356.05 was i suppose to divided ??

Answer 8

356.05 = perfect answer, nicely done

Answer 9

Giid job Moo Moo

Answer 10

Good

Answer 11

Thank you ^w^ and really geek lol

Answer 12

hurry up amanda

Answer 13

nice spelling there geek ;P

Answer 14

hey jack would it be ok if u could help me with 4 more questions :D

Answer 15

Ty Goku Jack

Answer 16

lol ;)

Answer 17

ill help too

Answer 18

yo, sure, close this one off tho, it's all LaTex'd up again

Answer 19

I hate the latex subject

Answer 20

oh ok ^w^ thank you