Question

plz help

Answer 1

its on the doc.

Answer 2

1. B

i would love to help.. but i dont know the rest
@Michele_Laino help

Answer 3

ok thx

Answer 4

http://assets.openstudy.com/updates/attachments/55857509e4b091b59af14393-foxycrew-1434809630481-1213.doc

Answer 5

yes! I confirm, the answer is:
\[\frac{1}{{\sin \theta }} = \csc \theta \]

Answer 6

help her for the rest

Answer 7

im a boy

Answer 8

hint:
when an object is moving, its position is a function of...?

Answer 9

@foxycrew

Answer 10

sorry @foxycrew

Answer 11

speed

Answer 12

I think, it is a function of time, am I right?

Answer 13

@foxycrew

Answer 14

your on 2 right??

Answer 15

yes!

Answer 16

is it a

Answer 17

I think option D, since frequency is the inverse of time

Answer 18

ok thx

Answer 19

ok! Let's go to question #3

Answer 20

ok

Answer 21

hint:
we have this relationship:

\[\Large a = c\cos \beta \]

Answer 22

so what is the right option?

Answer 23

um i say C or B

Answer 24

hint:
from the preceding formula, we can write:
\[\Large \cos \beta = \frac{a}{c}\]
there a is the adjacent side with respect to angle \beta, whereas c is the hypotenuse

Answer 25

im so lost

Answer 26

a is the adjacent side with respect to \beta, right?

Answer 27

and c is the hypotenuse

Answer 28

idk im on this to help me

Answer 29

http://www.themathpage.com/atrig/trigonometry-of-right-triangles.htm

Answer 30

so we can write:
\[\Large \cos \beta = \frac{a}{c} = \frac{{{\text{adjacent side}}}}{{{\text{hypotenuse}}}}\]

Answer 31

so its B.