Question

This cannot be solved can it?

I need to find c. Drawing is coming up.

Answer 1

This is not a 90 degree triangle

Answer 2

60 is 60 degree angle

Answer 3

its not a right triangle are you sure?

Answer 4

Yes, I thought it might of been but I asked my instructor and he said no. So I am assume it cannot be solved.

Answer 5

It can be solved but with some high tech trig stuffs. So I would just go with not able to be solved :)

Answer 6

Hummm I might of seen something

Answer 7

I am doing high tech trig stuff. Well I am working with Sine and Cosine laws.

Answer 8

Yes

Answer 9

If it was a right triangle you could use tangent and figure it out easily but im not sure since its not a right triangle

Answer 10

sorry ment cosine

Answer 11

I think I am on to something. BRB I might of solved it.

Answer 12

ok after could you help me on my problem? I would appreciate it im stuck lol

Answer 13

Yeah I solved it. I have to get b first. Then I can solve.



b = \( \tan60 = \frac{3}{b} \) After I find b I can solve with Sine Law. :-) I got it :-)

Answer 14

What is your problem?

Answer 15

i did @nicky on it check you inbox for the notifications to take you to the page

Answer 16

To use sine/cosine law,
you need any 3 out of 6 information (3 sides, 3 angles)

here you're given only 2 of those info....

Answer 17

Interesting question...

Did they give you any information? Or all they gave you was that triangle with 2 pieces out of the 6. (3 angles, and 3 sides.)

Answer 18

@AbdullahM did you see my last post where I stated I got it? I had to solve for b first and then I could use Sine Law. After I have b I have two sides and an angle which will allow me to solve the rest using Sine Law. tan 60 = 3/b which is 3 / tan 60 = b :-) I had to think about it for a minute but I got it.

Answer 19

Oh, so this refers to the previous post xD

So, we were given in the previous post:

A = 103 degrees
b =31
c=52

and we got in the previous post:

a=66.26
B=27.12 degrees

So, we can use either Law of Sines or Law of cosines...

\(\sf\Large \frac{sin103}{66.26} =\frac{sin27.12}{31}=\frac{sinC}{52}\)

Answer 20

But now that I look at the question again, they already gave you c as 52... and also, the angle became 60? o_0

Answer 21

@AbdullahM This does not refer to to a previous post. This is a totally separate post

Answer 22

oh, I get what you mean lol