Point X is located at (2, -6) and point Z is located at (0, 5). Find the y value for the point Y that is located the distance from point X to point Z. (4 points)

-3.6

-3.8

-4

-4.2

Question

Point X is located at (2, -6) and point Z is located at (0, 5). Find the y value for the point Y that is located  the distance from point X to point Z. (4 points)
		
-3.6
		
-3.8
		
-4
		
-4.2

anonymous · Answer

Wait, hm, is that the correct graph for this problem? The question mentions X Y and Z and I can't seem to find any of those on the shape.

tw101 · Answer

oh whoops! sorry wrong equation haha ignore that

anonymous · Answer

It's ok! :P

tw101 · Answer

okay so you were saying

tw101 · Answer

okay so you were saying

tw101 · Answer

The bottom question is what i was asking

anonymous · Answer

Is the original question the one you are confused on? the point X is located... etc?

karatechopper · Answer

Is Y somewhere between X and Z? Almost forming a triangle shaped...?

tw101 · Answer

sorry about that one sec

tw101 · Answer

I figured out the weird triangle one, now I just have a question about the point x one

karatechopper · Answer

Please rewrite the question below my comment, I am a bit confused about which exact question. Is the one that is your current question?

tw101 · Answer

Point X is located at (2, -6) and point Z is located at (0, 5). Find the y value for the point Y that is located  the distance from point X to point Z. (4 points)
		
-3.6
		
-3.8
		
-4
		
-4.2

anonymous · Answer

@tw101 , are you familiar with the 'Distance Formula' at all?

abdullahm · Answer

I believe it wants the midpoint...

anonymous · Answer

It says that point Y is located at the distance of point X to point Z, not between them I believe. But I could be mistaken.

tw101 · Answer

isnt it c^2=a^2+b^2?

abdullahm · Answer

"Find the y value for the point Y that is located  the distance from point X to point Z."

It could be asking for what y-value is the same distance from x as from z.

abdullahm · Answer

Also, trying to find the distance of it would not get us anywhere and midpoint makes more sense.

anonymous · Answer

Ah, okay that makes sense now

abdullahm · Answer

$\sf\Large Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

and that is for two points: $\sf (x_1,y_1)$ and $\sf (x_2,y_2)$

tw101 · Answer

okay give me a second to work it out:)

abdullahm · Answer

mhmm, the answer isn't there. So it isn't the midpoint :/

tw101 · Answer

wait im confused what do you mean

tw101 · Answer

i didnt get the right answer either...

tw101 · Answer

so what method can i use then..?

abdullahm · Answer

I'm not sure :/

tw101 · Answer

dang.. okay well thank you for your help anyways.