What is the equation in point-slope form of the line passing through (3, 6) and (−2, 1)?
Are there options?
Hmm. I'd say 1.
y + 6 = 1(x + 3) y + 1 = −1(x + 2) y − 6 = −1(x + 3) y − 6 = 1(x − 3)
I'd ask @Baseballguy101 He's good at this stuff.
do you know the formula first of all?
nope
ok it's y-y1 = m(x-x1). what do you think we shoud do from here?
6+2=m(1-3) idk
before we go further do you have a graph or is that it?
that's it
ok so with your equation being y-y1 = m(x-x1), m being slope, we will need to find this. Do you know how?
Given two points \((x_1,y_1),(x_2,y_2)\) first find the slope given by \(m=\dfrac{y_1-y_0}{x_1-x_0}\) and then choose any point (say the first one) and we have \[y=m(x-x_1)-y_1\]
i have nno idea about any of this to be honest
@nigel305 These sites might help you if you need to review the concepts. They are easy to read and help you recall what you have learned before. http://www.algebra.com/algebra/homework/Graphs/Slope-of-a-Line-between-two-points.lesson https://www.mathsisfun.com/algebra/line-equation-point-slope.html
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