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OpenStudy (anonymous):
Logarithms. Solve.. Log7 (x-4)-log7 (x+5)=log7 (3) Help please The 7 is the supposed to be the base of log
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OpenStudy (zzr0ck3r):
\(\log_7(x-4)-\log_7(x+5)=\log_7(3)\\\log_7(\dfrac{x-4}{x+5})=\log_7(3) \\ \dfrac{x-4}{x+5}=3\)
OpenStudy (anonymous):
Thanks
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