Question

A 0.200 kg block of a substance requires 3.59 kJ of heat to raise its temperature by 20.0 K. What is the specific heat of the substance?

A. 2,020 J/(kg * K)
B. 383 J/(kg*K)
C. 130 J/(kg * K)
D. 897 J/(kg*K)

Answer 1

the requested specific heat c is:
\[\large c = \frac{1}{m}\frac{Q}{{\Delta t}} = \frac{1}{{0.2}}\frac{{3.59}}{{20}} = ...\left( {Kjoules/Kg \times K} \right)\]

Answer 2

we get 0.8975? and converting we get choice D as our answer?

Answer 3

that's right!

Answer 4

yay! thansk!!

Answer 5

:)