Will give medal! How do I simplify the square root of the fourth root of 8 in exponential form?
\[\sqrt{\sqrt[4]{8}}=\sqrt{8^{\frac{ 1 }{ 4}}}=(8^{\frac{ 1 }{ 4 }})^{\frac{ 1 }{ 2 }}=8^{\frac{ 1 }{ 8}}=(2^{3})^{\frac{ 1 }{ 8 }}=2^{\frac{ 3 }{ 8 }}\]
But I'm confused on how you got that @peachpi
how is it confusing? things to power are multiplied with each other
square root is the same as the exponent ½ fourth root is exponent ¼
oh ok thank you @peachpi
@peachpi Would you mind if I ask you another question?
ok
How would I simply this expression in exponential form?
ok. this is the same type of problem. How would you write the numerator with an exponent?
3 and 1/2
exponents with bases being divided are subtracted eg. 3^(1/2) / 3^(1/4) = 3^ ((1/2) - (1/4))
Yeah. Then √3 is also a part of the denominator so you can do this |dw:1434904015717:dw|
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