Question

A 250.0 g metal block absorbs 7.849 × 10^3 J of heat to raise its temperature by 35.0 K. What is the substance?

***How can I explain and show the work for this?
will attach the corresponding table inside!! thanks!! @michele_laino :)

Answer 1

here we have to compute the specific heat, as follows:
\[\large c = \frac{1}{m}\frac{Q}{{\Delta t}} = \frac{1}{{0.25}}\frac{{7.849 \times {{10}^3}}}{{35}} = ...J/(Kg \times ^\circ K)\]

Answer 2

ok! so we get 897.0285 ?

Answer 3

yes!

Answer 4

now, look at your table

Answer 5

yay!! so this means our substance is aluminum?

Answer 6

that's right!

Answer 7

yay! thank you !! so that is it for this problem? :O

Answer 8

yes! we have finished!

Answer 9

yay!! thank you!! i will post the next one now:)

Answer 10

:) ok!