Question

I need help with Chemistry.

Answer 1

Change these word equations into formula equations and balance them. Be sure to use the proper symbols to indicate the state of each substance, as given.

1. Solid calcium hydroxide reacts with aqueous chloric acid to form a solution of calcium chlorate along with liquid water.

2. Zinc metal is placed into a solution of acetic acid, producing hydrogen gas and aqueous zinc acetate.

3. Solutions of sodium carbonate and cobalt(II) chloride react to form solid cobalt(II) carbonate and a solution of sodium chloride

Answer 2

Well lets go over the one at a time. Since you are not on right now, I'm not sure how much you know about balancing equations and how well you are at reading the periodic table so I will do the first one and you can do the rest as it will be similar but if you're still stuck please ask!

Ok, so calcium hydroxide solid is as the following \[CaOH_2(s)\] notice using your periodic table calcium has a charge of 2+ and if you look on the polyatomic ions side of the table hydroxide has 1-, so we have to balance the compounds as presented above.
Now aqueous chloric acid, chloric acid is the following \[HClO_3(aq)\] we use chlorate because "chloric acid" ends in ...ic, so we use ....ate of which ever compound. If it said hydro...ic, then we would use chloride, because for hydro...ic, we use ...ide, and if it ended in ...ous, we use chlorite, ...ite. (Hope that makes some sense).
Calcium chlorate is the following \[Ca(CLO_3)_2\] notice we balance it again since Ca has a charge of 2+ and chlorate has a charge of 1-
Finally liquid water is just \[H_2 O(l)\]

Now lets balance it!

Answer 3

Note that calcium hydroxide should have brackets so it should be \[Ca(OH)_2(s)\]
\[CaOH_2(s) + HClO_3(aq) \implies Ca(ClO_3)_2 + H_2 O(l)\] so here is our equation, now the tricky part is to balance it.

\[Ca(OH)_2(s) + 2HClO_3(aq) \implies Ca(ClO_3)_2 + 2H_2 O(l)\] and that should do it!

Answer 4

So for the balancing part (adding the coefficients) we see on the right side there were 2 "chloric acids" so we had to balance that with the left by multiply the whole equation of aqueous chloric acid by 2, in doing so we had 4 hydrogens in total then, so we went back to the right side and balanced it by adding a 2 in front of the water. Hope that helped!