Question

Given: AB .BE = CB . BD
Prove: Triangle ABC is similar to triangle DBE

Answer 1

Please help me

Answer 2

Thanks for trying

Answer 3

I don't understand the given. Could you please type it correctly?

Answer 4

I have not had Geometry, I watched a video explaining AA SAS and SS

Answer 5

\[(AB)(BE)=(CB)(BD)\]
\[\frac{(AB)(BE)}{(BE)(BD)}=\frac{(CB)(BD)}{(BE)(BD)}\]
\[\frac{(AB)}{(BD)}=\frac{(CB)}{(BE)}\]

Answer 6

So now we have established that corresponding sides have equal ratios.

Answer 7

Now use the fact that vertical angles are congruent and you have SAS similarity.

Answer 8

I knew about vertical angles

Answer 9

thanks

Answer 10

yw