Given the functions f(x) = x2 + 6x − 1, g(x) = –x2 + 2, and h(x) = 2x2 − 4x + 3, rank them from least to greatest based on their axis of symmetry.

f(x), g(x), h(x)
h(x), g(x), f(x)
g(x), h(x), f(x)
h(x), f(x), g(x)

Question

Given the functions f(x) = x2 + 6x − 1, g(x) = –x2 + 2, and h(x) = 2x2 − 4x + 3, rank them from least to greatest based on their axis of symmetry.

 f(x), g(x), h(x)
 h(x), g(x), f(x)
 g(x), h(x), f(x)
 h(x), f(x), g(x)

campbell_st · Answer

do you know how to find the axis of symmetry..?

anonymous · Answer

not when it is in standard form

karatechopper · Answer

You would need to convert to vertex form right? @campbell_st

anonymous · Answer

nvm -b
        ---
         2a right?

campbell_st · Answer

ok... so if an parabola is in the form 

$$y = ax^2 + bx + c$$

the axis of symmtery is 

$$x = \frac{-b}{2a}$$

this may be familar as its part of the general quadratic formula 

so on the 1st question you have a = 1  and b = 6 

so the axis of symmetry is 

$$x = \frac{-6}{2 \times 1}$$

just solve it

hope that makes sense

campbell_st · Answer

then repeat the process for the 2nd and 3rd equations.

anonymous · Answer

so fgh? A

campbell_st · Answer

makes sense to me

anonymous · Answer

not A