Question

What is the oxidation number for iodine in Mg(IO3)2 ?

Answer 1

\[\rm Mg(IO_3)_2\] ?

Answer 2

You should be able to firstly place the oxidation numbers of the main ions.
For instance, group 1 ions have +1
Group 2 have +2
Hydrogen has +1
Oxygen has -2
For a given compound, you have to make an equation of the oxidation number of all elements present, equating them to zero.
Simplifying that equation, we get \[MgI _{2}O _{6}\]
For Mg we have 1 atom, for I we have 2 and for O, 6.
The equation then becomes\[+2+2x+(-2*6)=0\]

Answer 3

\[2x=10\]
\[x=5\]

Answer 4

Good Work :)

Answer 5

Nice hearing that, @rvc.