Question

Find the rate of change

Answer 1

ummm

Answer 2

let me try

Answer 3

okk

Answer 4

answer choice?

Answer 5

@aloud can you help me out?

Answer 6

it's not any answer choices

Answer 7

kind in a tight situation

Answer 8

i have to go in couple min

Answer 9

lol ya ik me to

Answer 10

@H3LPN33DED help plz?

Answer 11

@TillLindemann

Answer 12

sorry dianolove idk this one i am only in geometry

Answer 13

it's okk

Answer 14

(1,2) (2,3)

Answer 15

@braydenbunner

Answer 16

@aloud, that would be an approximation of the rate of change

Answer 17

however, at the point (2,3) -tangent to curve you would have an exact rate of change

Answer 18

so the rate of change is (2,3)

Answer 19

The way to solve this exercise is to first find the equation of the parabola, followed by the derivative of it and for that you will have to choose a particular x - value.

Answer 20

like (2,1)

Answer 21

What aboyt the reverse, @Hoslos , if you know the derivative at a point, can you integrate to find original function?

Answer 22

Let us find the equation of the parabola, using the formula:
\[y=a(x-p)^{2}+q\], where x,y is from any coordinate of the graph and p and q are the x and y - values of the vertex, respectively.
The first attempt is to find a . Replacing values, we get:
\[1=a(1-3)^{2}+2\]
\[1=a(-2)^{2}+2\]
\[1-2=4a\]
\[a=-0.25\]
Next we re-write the equation, by now putting a and the vertex coordinates, giving us:
\[y=-0.25(x-3)^{2} +2\]

Answer 23

Well, the rate of change will have to end at the derivative, which will mean the change in y with respect to x, @BPDlkeme234 .

Answer 24

i'm sorry this is just hard

Answer 25

As for the second part, you differentiate the equation of the formula:
\[\frac{ d _{y} }{ d _{x} }= -0.5(x-3)\]
There it is. Depending on the question, they would tell you a particular value of x runing in the graph.
For instance let us say, when the x-value is 2. The rate of change will be \[-0.5(2-3)=0.5units/time\]
Any question on differentiation, please ask.

Answer 26

thanks for tryin i still dont get it but thanks