Question

Please help me out. :)

Answer 1

ok

Answer 2

Sure

Answer 3

#208 only. :) thankyou.. ^_^

Answer 4

Can you please type the question so it is easier to see

Answer 5

oww.. okay.. sure. :) wait a minute..

Answer 6

Can you see it clear?

Answer 7

Yep thanks let me find the answer

Answer 8

thankyou.. :) i'll try to answer it again. ^_^

Answer 9

Hey there.
We will have to use Pythagoras here, part of Mechanics exercises.

Answer 10

ahh.. but how to illustrate the several forces?

Answer 11

Relax, I will show you.

Answer 12

For a, you will have diagrammatically, the following representative situation

Answer 13

Finding the hypotenuse will be the resultant force:
\[DeltaP=\sqrt{(-200)^{2}+100^{2}}=223.7=224N\]
For the angle, we can use Sine function, giving us\[\sin \beta=\frac{ 200 }{ 224 }\]
\[\beta=\sin^{-1} \frac{ -200 }{ 224 }=-63.2\]
Given that you do not want negative angles, we use the property 90-B=90-63.2=26.7Degrees.
Can you use the same methodology for the other exercises?

Answer 14

What do you mean?