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Geometry 6 Online
OpenStudy (anonymous):

Please help. I will MEDAL and FAN!!!!! Referring to the figure, on the right triangle shown, find the unknown side length. (If necessary, round to the neartest tenth.)

OpenStudy (anonymous):

|dw:1434987008886:dw|

OpenStudy (anonymous):

@CallMeKiki @sugarplum15

OpenStudy (anonymous):

is that a right angled triangle ?

OpenStudy (anonymous):

No. It doesn't have the box in the corner

OpenStudy (anonymous):

its mentioned that its a right angled triangle

OpenStudy (anonymous):

use pythagoras

OpenStudy (anonymous):

have you been able to do ?

OpenStudy (anonymous):

So a^2 would be 8.

OpenStudy (anonymous):

And 20 would be c^2?

OpenStudy (anonymous):

\[a ^{2} = b ^{2} + c ^{2}\] replace a by 20, b by x and c by 8 \[(20)^{2} = (x)^{2} + (8)^{2}\]

OpenStudy (anonymous):

@OM14forever better now ?

OpenStudy (anonymous):

how do I find x

OpenStudy (anonymous):

20/8=

OpenStudy (anonymous):

is that what I should do

OpenStudy (anonymous):

\[x ^{2} = 20^{2} - 8^{2}\]

OpenStudy (anonymous):

so 12

OpenStudy (anonymous):

\[x ^{2}= 400 - 64\] \[x ^{2} = 336\] \[x = \sqrt{336} = 18.3\]

OpenStudy (anonymous):

nearest to tenth will be x= 18

OpenStudy (anonymous):

ok thanks

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