Select the inequality that models the problem.

The length of a rectangle is twice its width. If the perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?

Question

Select the inequality that models the problem. 

The length of a rectangle is twice its width. If the perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?

anonymous · Answer

2 • 2w + 2w < 50
       2 + 2w < 50
       2w • w < 50
       2w < 50

anonymous · Answer

option a

anonymous · Answer

the reason being that...if w is the width of the rectangle, then 2w will be the length of the rectangle.......
perimeter is = 2(l+b)
=2(2w+w)=2.2w+2w....got it?

anonymous · Answer

this 
2.2w+2w has to be less that 50

trojanpoem · Answer

L = 2 W       2L + 2W < 50           4W + 2W < 50   6W < 50  W < 25/3