Question

Select the inequality that models the problem.

The length of a rectangle is twice its width. If the perimeter of the rectangle is less than 50 meters, what is the greatest width of the rectangle?

Answer 1

2 • 2w + 2w < 50
2 + 2w < 50
2w • w < 50
2w < 50

Answer 2

option a

Answer 3

the reason being that...if w is the width of the rectangle, then 2w will be the length of the rectangle.......
perimeter is = 2(l+b)
=2(2w+w)=2.2w+2w....got it?

Answer 4

this
2.2w+2w has to be less that 50

Answer 5

L = 2 W 2L + 2W < 50 4W + 2W < 50 6W < 50 W < 25/3