Question

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

a. y = -2x - 4
b. y = -2x + 18
c. y = -2x - 8
d. y = -2x – 12

Answer 1

Given a line passing through a point with coordinates (x1, y1) and having a slope of m, the equation of that line can be given by:

\[y - y _{1} = m(x - x _{1})\]

So, by substituting in our values for x1, y1 and m into the above and rearranging to get y on its own, you should have the answer. Hope that helps! :)

Answer 2

Can you show me how lol

Answer 3

For our line, we have a point (2, -8) that it passes through and a slope of -2. We now need to label our x1, y1 and m, as I talked about in my previous post. So,

x1 = 2
x2 = -8
m = -2

Now, replace the x1, y1 and m in our general equation for the line with 2, -8 and -2 respectively. This will give us:

\[y -(-8) = -2(x -2)\]
or
\[y + 8 = -2(x - 2)\]

Then, it's a case of multiplying out the bracket on the right-hand side of the equation and isolating the 'y' term on its own on the left-hand side so that your equation looks like one of the options listed in the question.

Answer 4

y = -2x -4
a.