Question

Can someone help me with this problem. A right triangle has coordinates A(6, 0), B(0, 0), and C(0, 8). What is the perimeter of the triangle?

Answer 1

When you have coordinates, use the formula of Pythagoras to find the lengths:\[l=\sqrt{(y _{1}-y)^{2}+(x _{1}-x)^{2}}\]

No we find the lengths AB, AC and BC.

Answer 2

When you have coordinates, use the formula of Pythagoras to find the lengths:\[l=\sqrt{(y _{1}-y)^{2}+(x _{1}-x)^{2}}\]

No we find the lengths AB, AC and BC.

Answer 3

Given coordinates, to find the lengths, we will have to use Pythagoras theorem:\[l=\sqrt{(y-y _{1})^{2}+(x-x _{1})^{2}}\]

Answer 4

\[AC=\sqrt{(8-0)^{2}+(0-6)^{2}}=10\]
\[AB=\sqrt{(0-0)^{2}+(0-6)^{2}}=6\]\[BC=\sqrt{(8-0)^{2}+(0-0)^{2}}=8\]
\[P=s_{1}+s _{2}+s _{3}=6+8+10=24units\]