Amy is playing a board game and rolls two number cubes. Let A = {the sum of the number cubes is odd}, and let B = {the sum of the number cubes is divisible by 3}. List the outcomes in A ∪ B.
The possible sums of two number cubes \(\in \Omega =\{{2,3,4,5....11,12}\}\) A={3,5,7,9,11} ..... odd sum B={3,6,9,12}...... outcome divisible by 3 So what is A\(\cup\)B ? See following link for an explanation of set operators. http://www.mathsisfun.com/sets/venn-diagrams.html
Ohhh so this {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} is not the answer?
1 is not a possible outcome if we are looking for the sum of the number cubes. See my previous post for help.
No, this is the set of possible sums when we throw two number cubes! There are conditions to A and B, and you need to find \(A\cup B\).
Oh then it would be {3, 5, 6, 7, 9, 11, 12} right?
Yes, {3, 5, 6, 7, 9, 11, 12} is A \(\cup\) B
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