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How can I turn this into a fraction... (1-3x)^(3/x)
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take the log first
would that become \[(\frac{ 3 }{ x })\ln(1-3x)\]
or else use the definition \[(1-3x)^{\frac{3}{x}}=\exp\left(\frac{3\log(1-3x)}{x}\right)\] the work will be identical in either case
yes it would
then use l'hopital , then whatever you get for the limit, raise e to that power
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Ahh I see thanks so much! :D
actually now that i look, it doesn't say that this is a limit question, but i am almost certain it is right?
yw
Haha yep! It is :D one of the l'hopital rule limits xP
how'd i guess?
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Smarty pants :P
lol
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