Question

functions

Answer 1

\(\large \color{black}{\begin{align} & \normalsize \text{Find the minimum value of the function}\hspace{.33em}\\~\\
& f(x)=\log_{2} (x^2-2x+5) \hspace{.33em}\\~\\
\end{align}}\)

Answer 2

IDK

Answer 3

make roots of the equation then use both roots to find the answer

Answer 4

unlikely since you cannot take the log of zero

Answer 5

find the minimum value of the quadratic

Answer 6

roots are imaginary here

Answer 7

which will be the second coordinate of the vertex

Answer 8

vertex of \[x^2-2x+5\] should be easy enough to find

Answer 9

since log is an increasing function, once you find the minimum value of the quadratic, that will give you the input that produces the minimum value of the log

Answer 10

minimum is 5

Answer 11

no it is not

Answer 12

the second coordinate of the vertex is not 5, the constant is 5

Answer 13

i put x=0 here x^2-2x+5

Answer 14

yeah sure, if you put in 0 you get 5, but the vertex is NOT \((0,5)\)

Answer 15

use \[-\frac{b}{2a}\] to find the first coordinate of the vertex

Answer 16

whats the minimum value of \(x^2 - 10000000x + 1\) ?

Answer 17

plug that in to find the second coordinate ( it is definitely not 5)

Answer 18

yes

Answer 19

misty its girl like u that i study maths u are eaiutiful

Answer 20

thank you darling, you look pretty cute yourself

Answer 21

i should change my profile pic

Answer 22

oh i remember that dy/dx=0, minimum is 4

Answer 23

lol pick a cute girl, everyone will love you

Answer 24

btw can u explain it with solutionj plz

Answer 25

yeah min is 4 and \[\log_2(4)\] is your answer

Answer 26

wait let me search cute girl pics
damn those are some fine kittens

Answer 27

you certainly don't need to use calc to find the vertex of a quadratic though...