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Mathematics 11 Online
OpenStudy (tbnrfrags):

(v-8)^2 help pl0x

OpenStudy (anonymous):

Do you want to expand the expression?

OpenStudy (astrophysics):

\[(v-8)^2 \implies (v-8)(v-8)\]

OpenStudy (anonymous):

Use the foil method.

OpenStudy (owlcoffee):

I'll give you a hint: \[(a-b)^2 = a^2 -2ab +b^2 \]

OpenStudy (tbnrfrags):

http://prntscr.com/7kj71y this is the whole thing...

OpenStudy (anonymous):

Ah, its \[(3v-8)^2\]

OpenStudy (anonymous):

Just rewrite it as \[(3v-8)^2 = (3v-8)(3v-8) = \]

OpenStudy (anonymous):

Do you know how to use the foil method to expand?

OpenStudy (tbnrfrags):

No idea

OpenStudy (anonymous):

You expand each term one by one.

OpenStudy (anonymous):

\[(3v - 8)(3v - 8) = 3v*3v - 8*3v - 8*3v + 8*8\]

OpenStudy (anonymous):

To approach binomial expansion of any order, you must first understand how the foil method works.

OpenStudy (tbnrfrags):

so its B?

OpenStudy (anonymous):

But what about the v term?

OpenStudy (anonymous):

After you combine the like terms, you should get something like\[9v^2-48v+64\]

OpenStudy (anonymous):

The only time when the middle term cancels out is when the signs are opposite. Check out conjugate multiplication for more information.

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