Question

1. Find the first six terms of the sequence.
a1 = -8, an = 5 • an-1
-8, -40, -200, -1000, -5000, -25,000
-8, -40, -35, -30, -25, -20
0, 5, -40, -35, -30, -25
-40, -200, -1000, -5000, -25,000, -125,000

2.) Find an equation for the nth term of the arithmetic sequence.
a(subscript)19 = -58, a(subscript)21 = -164

an = 896 - 53(n - 2)
an = 896 - 53(n - 1)
an = 896 + 53(n + 1)
an = 896 - 53(n + 1)

3. Find an equation for the nth term of the arithmetic sequence.

-1, 2, 5, 8, ...

an = -1 + 3(n)
an = -1 + 3(n - 1)
an = -1 + 3
an = -1 + 3(n + 1)

Answer 1

q1.

Answer 2

a2 = 5.a1 = 5*-8 = -40
a3 = 5*a2 = 5*-40 = -200
a4 = 5*-200 = -1000 and so on. So, the answer is a @em2000

Answer 3

got it @princeharryyy

Answer 4

q2.

Answer 5

a19 = a + 18d = -58. let it be 1
a21 = a + 20d = -168 let it be 2

equation(2-1)
a+20d - a-18d =-164 +58
2d = -106
d = -53

putting in 1
a=-58+18*53 = 954-58 = 896

Answer 6

so answer => 896 -53(n-1) @em2000

Answer 7

that's is b. r u getting it. @em2000

Answer 8

an for any ap is given as
an = a + (n-1)*d
is known as general term @em2000 u getting.

Answer 9

q.3

Answer 10

-1, 2, 5, 8, ...

a= -1 given
-1+3 =2, 2+3 =5, 5+3=8 and so on
so common difference d =3
hence

an = -1 +(n-1)*3 @em2000

Answer 11

thank u so much @princeharryyy

Answer 12

:)