Question

Which of the following could be used to calculate the area of the sector in the circle shown above?
π(10in)^2 37 over 360 <---- my answer
π(10in)37 over 360
π(37in)210 over 360
π(37in)10 over 360

Answer 1

@mathmath333

Answer 2

hmmm what lead you to think so?

Answer 3

well i thought it was that because since r= 10 but i was a little unsure if it was right

Answer 4

well \(\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad
\begin{cases}
\theta=37\\
r=10
\end{cases}\implies \cfrac{37\pi 10^2}{360}\)

Answer 5

oh ok so then it would be C right ?

Answer 6

hmmm ahemm \(\bf \textit{sector of a circle}=\cfrac{\theta\pi r^2}{360}\qquad
\begin{cases}
\theta=37\\
r=10
\end{cases}\implies \cfrac{37\pi 10^2}{360} \iff \cfrac{\pi 10^2 37}{360}\)

commutative property

Answer 7

You're right @Moo_Moo17
It is A indeed. If angle is 360 then we get the area of the whole circle. It should be proportional to the square of the radius. \[S = r ^{2}37\]
And there should be angle of the sector and we know that for the circle the area is:
\[\pi r^2\]
So, if our sector is 360 degrees we have to get full circle.

Answer 8

oh ok thank yo so much miracrown ^w^

Answer 9

yw :)