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write the equation that has amplitude=4 & period=pi/2
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You don't say whether it's sine or cosine, but the format is \[y=A \cos (B \theta)\] where A is the amplitude and \[B=\frac{ 2 \pi }{ period }\]
its sin
@peachpi
it's still the same formula. Just change cos to sin
ok how bout if the amp was like 1/3 would A be 3? @peachpi
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no it would be 1/3
ok lol thanks last question sorry how bout if the period is 2pi/period & the period is pi/2 what would the answer be? i keep getting different answers @peachpi
are you saying the period is 2pi or the period is pi/2?
and you're asking how to find B?
pi/2 & yes finding b @peachpi
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