Question

3tanx3-10tanx=0 , in the domain 180 10 years ago

Answer 1

excuse me is it tan3x or tanx3

Answer 2

tanx^3

Answer 3

sorry i mean tanx^2

Answer 4

so 2tanx^2 -10tanx

Answer 5

omggg 3tanx^2 -10tanx

Answer 6

@nincompoop

Answer 7

@abb0t

Answer 8

Is it \[\Large 3\tan(x^2) - 10\tan(x)=0\]

or


Is it \[\Large 3\left(\tan(x)\right)^2 - 10\tan(x)=0\]

??

Answer 9

the second one

Answer 10

you can let z = tan(x)

that gives

\[\Large 3z^2 - 10z = 0\]

\[\Large z(3z - 10) = 0\]

agreed?

Answer 11

actually the x is the angle sign

Answer 12

yep i get those steps dk what to di next

Answer 13

so if z(3z-10) = 0, then either z = 0 or 3z-10 = 0 by the zero product property

Answer 14

re-substitute in z = tan(x)

z = 0 turns into tan(x) = 0

3z-10 = 0 turns into 3*tan(x) - 10 = 0

Answer 15

jim we need to consider the xrange of x
i also got here but the range got me confused

Answer 16

true, that's a good point

Answer 17

ok i get this whats next

Answer 18

solve tan(x) = 0 and 3*tan(x) - 10 = 0

and make sure 180<x<360

Answer 19

use the arctan function on a calculator to undo the tan function

Answer 20

or we can put the range

Answer 21

tan 0 i get 0 , for other i get 73.300

Answer 22

is x = 0 in the interval 180<x<360 ?

Answer 23

is x = 73.3 in the interval 180<x<360 ?

Answer 24

umm

Answer 25

yea that the part i am stuck on

Answer 26

if it is, then you can keep the solution

if not, then add/subtract 180 until you get in the interval

Answer 27

being in the interval means that the number is between 180 and 360

Answer 28

ok 73 is

Answer 29

nope, 73 is not between 180 and 360

Answer 30

no i mean when i add 180

Answer 31

oh ok

Answer 32

excuse since its periodic the range can be taken in 0<x<180
or 0<x<2pie

Answer 33

k got the answer thank you

Answer 34

no problem

Answer 35

thanks jim

Answer 36

u guy can stick around ? i got more

Answer 37

oky woul love to in any way