Question

Solve the following quadratic equation using the quadratic formula and then choose the correct solution set.

6x2 - 7x + 2 = 0

Answer 1

\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 2

@dominique2525 Thats not one of the options. These are the options:
{-1/2,2/3}
{1/2,2/3}
{1/2,3/2}

Answer 3

I got dominiques answer too, but how come its not one of the choices? :/

Answer 4

I think there is a significant error in the calculations

\[x =\frac{ 7 \pm \sqrt{(-7)^2 - 4 \times 6 \times 2}}{2 \times 6}\]

which becomes

\[x = \frac{7 \pm \sqrt{49 - 48}}{12}\]

Answer 5

How do i figure out what the solution set is?

Answer 6

and just to show your teacher, this quadratic can be factored

multipily a and c 6 x 2 = 12

find the factors of 12 that add to -7.... they are both negative -3, -4

then write the factored equation as

(6x -3)(6x -4)
------------
6

factor the linear factors

3(2x -1) 2(3x -2)
---------------
6

remove the common factors

(2x -1)(3x -2) = 0

now you can find the values

Answer 7

well to get the solution simplify the square root

\[x = \frac{7 + \sqrt{1}}{12}~~~~and~~~~~ x = \frac{7 - \sqrt{1}}{12}\]

what is the value of \[\sqrt{1} = ?\]

Answer 8

1?

Answer 9

great so you have 2 answers

\[x = \frac{7 + 1}{12} ~~~~and~~~~x = \frac{7 -1}{12}\]

just simplify them

Answer 10

@campbell_st Thank you so much!!! ugh i finally understand!!!!!

Answer 11

you made the calculation error inside the square root

(-7)^2 - 4 x 6 x 2 you someone posted -49 - 48 = 97

it should 49 - 48 = 1