Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

f(x) g(x)

OpenStudy (marinos):

Do you mean the following functions ? \[f(x)=-4\left( x-6 \right)^{2}+3\] and \[g(x)=2\cos \left( 2x-\pi \right)+4\]

OpenStudy (anonymous):

yes @marinos

OpenStudy (anonymous):

The maximum of cosine is 1, then g max is 2+4=2 The the vertex of the flipped parabola is when is 0, cause it's negative otherwise. So f max is 0+3 =3

OpenStudy (anonymous):

can you explain how @Ahmad-nedal

OpenStudy (marinos):

Remember that a square is always non-negative and that the absolute value of (sine and) cosine function(s) is at most 1.

OpenStudy (anonymous):

But the thing is, these two values are not satisfied at the same x coordinate, I think you will now be needing calculus 1 to find that point where x gets you the maximum

OpenStudy (anonymous):

What is your grade right now @jacey.stewart ?

OpenStudy (anonymous):

You use equation x=-b/2a to find the maximum Im just confused on the cosine part

OpenStudy (anonymous):

B

OpenStudy (anonymous):

The maximum of any sinsouidal function (since, cosx) is 1, therefore the maximum of cosine is 2

OpenStudy (marinos):

We have that \[\left( x-6 \right)^{2}\ge0\] since it is a square. Therefore \[-4\left( x-6 \right)^{2}\le0\] so \[f(x)=-4\left( x-6 \right)^{2}+3\le3\] implying that the maximum value of the function \[f(x)\] is 3. Can you argue similarly for the other function ?

OpenStudy (anonymous):

In my opinion, I think the question is not well written. Again if the maximum of f and g are achieved in two different x coordinates. Thus you cannot determine which point gives you the maximum MULTIPLE OF F(X) AND G(X)

OpenStudy (anonymous):

I repeat, you may need deffrentiation to find the maximum of f times g

OpenStudy (anonymous):

Is what I'm saying make sense jacy?

OpenStudy (marinos):

@Ahmad-nedal No differentiation is needed for these functions. There maximum value can be obtained using inqualities.

OpenStudy (anonymous):

I think it ultimately asked for the maximum of the multiple of F and G, isn't she?

OpenStudy (marinos):

Since \[\cos \left( 2x-\pi \right)\le1\] we have \[2\cos \left( 2x-\pi \right)\le2\] so \[g(x)=2\cos \left( 2x-\pi \right)+4\le2+4=6\] therefore the maximum value of this function is 6, and it is the greatest of the maximum values of the two initial functions.

OpenStudy (marinos):

@Ahmad-nedal I didn't see any reference to the product of f(x) and g(x) (in which case you do need differentiation to find the max value)

OpenStudy (anonymous):

Then you are right, it will be kinda trevial if considered two separate questions Thanksfor clarification

OpenStudy (marinos):

You are welcome.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!