Question

Approximate a critical number of y = x^3 + e^−x using Newton’s method

Answer 1

Critical numbers are where the derivative is 0 or doesn't exist. Did you find the derivative?

Answer 2

Ohh okay got it! I was a little confused on what it was xD

Answer 3

ok

Answer 4

Wait so the derivative is \[3x^2 - e^x\] right?

Answer 5

\[3x^2-e ^{-x}\]

Answer 6

hmm okay! thanks :)

Answer 7

I think I'm doing this completely wrong lol... I misunderstood the question!

Answer 8

Approximate a critical number of y = x^3 + e^−x using Newton’s method

Answer 9

That's the question

Answer 10

Not really sure how many roots the derivative has, but I guess start with xn = 0