Use the following scenario to answer the question:
A bag contains 5 green marbles, 4 red marbles, 7 blue marbles, and 9 yellow marbles.

If 3 marbles are drawn from the bag one at a time but replaced each time, what is the probability of drawing a green, red and yellow marble in that order?
a. 7/506
b.36/3125
c.2/3
d.1/96

Question

Use the following scenario to answer the question:
A bag contains 5 green marbles, 4 red marbles, 7 blue marbles, and 9 yellow marbles.

If 3 marbles are drawn from the bag one at a time but replaced each time, what is the probability of drawing a green, red and yellow marble in that order? 
a. 7/506 
b.36/3125
c.2/3
d.1/96

sloppycanada · Answer

K so - Welcome to multiplication. We do this because the events are not reliant on each other, the marble is replaced each time. 
Multiply the following together - 

$$\frac{ 5 }{ 25 } x \frac{ 4 }{ 25 } x \frac{ 9 }{ 25 }$$

anonymous · Answer

180/15625  ?

anonymous · Answer

idk how to simplify though

sloppycanada · Answer

Find a common multiple. Can 15625 be divided by ten?

sloppycanada · Answer

Can it be divided by 5? 3?

anonymous · Answer

by 10  its 1562.5 
by 5 its 3125 
by 3 its 5208.3 
so my guess is it would be by 5 ?

sloppycanada · Answer

Yup! Can you divide 3125 by any of the following - 

6 - ?
3 - ? 
2 - ? 

If yes, which one? If not, then 36/3125 is your answer.

anonymous · Answer

no not by any i think your right its 36/3125 !

anonymous · Answer

is there any way to simplify it agien ? i got the answer wrong :(

sloppycanada · Answer

There shouldn't be. They're all mutually exclusive events since the marble is replaced.

anonymous · Answer

alrighty then thanks ! (: