Question

Consider this system of equations:

23x+35y=12 (equation A)

52y−3x=6 (equation B)

The expression that gives the value of x is .
The solution for the system of equations is

Answer 1

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Do you know how to solve by substitution, elimination, or by graphing?

Answer 2

23x+35y=12;−3x+52y=6
Step: Solve 23x+35y=12 for x:
23x+35y+−35y=12+−35y(Add -35y to both sides)
23x=−35y+12
23x23=−35y+1223(Divide both sides by 23)
x=−3523y+1223
Step: Substitute (−3523y+1223) for x in −3x+52y=6:
−3x+52y=6
−3(−3523y+1223)+52y=6
130123y+−3623=6(Simplify both sides of the equation)
130123y+−3623+3623=6+3623(Add 36/23 to both sides)
130123y=17423
130123y130123=17423130123(Divide both sides by 1301/23)
y=1741301
Step: Substitute (1741301) for y in x=−3523y+1223:
x=−3523y+1223
x=−3523(1741301)+1223
x=4141301(Simplify both sides of the equation)
Answer:
x=414/1301 and y=174/1301

Answer 3

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