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Mathematics 10 Online
OpenStudy (leann01xxx):

A class has 20 students. If the teacher is randomly putting students in groups of 3 to complete a project, what is the probability that three students who are best friends will be together? 1/20 3/20 1/1,140

OpenStudy (anonymous):

easy way or hard way or both?

OpenStudy (anonymous):

actually even the hard way is not that hard

OpenStudy (leann01xxx):

It doesn't matter, just a way that i'll understand it.

OpenStudy (anonymous):

ok lets compute the number of ways to choose 3 people out of a set of 20, called "20 choose 3" and written as \(\binom{20}{3}\) or \(_{20}C_3\)

OpenStudy (anonymous):

easy to do with a calculator, it is a rather large number do you know how to compute it?

OpenStudy (leann01xxx):

One sec. Let me get my calculator.

OpenStudy (anonymous):

easier to use this http://www.wolframalpha.com/input/?i=20+choose+3

OpenStudy (leann01xxx):

OKay so is it 3/20?

OpenStudy (anonymous):

oh no

OpenStudy (anonymous):

did you open the link i sent? \[_{20}C_3=1440\]

OpenStudy (anonymous):

that is the number of possible groups of 3 only one of them has all three best friends, so probability is \[\frac{1}{1440}\]

OpenStudy (leann01xxx):

Yeah I did.

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