Question

geometry help please !! medal! What is the missing step in the given proof?
PCQ and ACP are supplementary by the Linear Pair Theorem.
For parallel lines cut by a transversal, corresponding angles are congruent, so ACB PCQ.
OCP BCD by the Vertical Angles Theorem.
For parallel lines cut by a transversal, corresponding angles are congruent, so OCP ABC.
For parallel lines cut by a transversal, corresponding angles are congruent, so OCA CBD.

Answer 1

Given: || , and || .


Prove: PCQ is complementary to ABC.
Proof: Since , mOCQ = 90° by the definition of perpendicular lines. By angle addition, we can say mOCQ = mOCP + mPCQ. But since mOCQ = 90°, mOCP + mPCQ = 90° by the Transitive Property of Equality.

[Missing Step]

By the definition of congruent angles, mOCP = mABC. This leads to
mABC + mPCQ = 90° by the Transitive Property of Equality. So, based on the definition of complementary angles, PCQ is complementary to ABC.

Answer 2

segment AC parallel to BD and AB is parallel to CD and AC id perpendicular to CD