Question

Write the equation of the circle whose center is at the origin and whose diameter is 12.

Answer 1

center is at the origin, (that is center at point (0,0), so h=0, k=0)

diameter is one half of the radius, so if diameter is 12 then radius is how long?

(hope you got this part, and now I will remind you to equation of the circle form)
\(\Large\color{black}{ \displaystyle (x-{\bf \color{red}{h}} )^2+ (y-{\bf \color{blue}{k}} )^2 = {\bf \color{green}{r}}^2 }\)

Where
1) \(\large\color{black}{ \displaystyle({\rm \color{red}{h}} ,~{\rm \color{blue}{k}} )}\) is the \(\normalsize\color{red}{ \bf c\color{blue}{e}n\color{blue}{t}e\color{blue}{r} }\) of the circle.
2) \(\large\color{black}{ \displaystyle {\rm \color{green}{r}} }\) is the \(\normalsize\color{green}{ \bf radius }\) of the circle.

Answer 2

There is no picture for me to find out what the middle of the circle is!?

Answer 3

you don't need pics

Answer 4

do you know how to fill out the

\(\large\color{black}{ \displaystyle (x-{\rm \color{red}{h}} )^2+ (y-{\rm \color{blue}{k}} )^2 }\)

?

Answer 5

no

Answer 6

well, your center is (0,0)
that means
h=0
k=0

Answer 7

something isn't clear?

Answer 8

What do you mean!?

Answer 9

I am asked you if you are confused about something in my explanation? I am asking you that because you don't seem to manage to fill out the left side of the equation of the circle

((( The equation of the circle: \(\large\color{black}{ \displaystyle (x-{\rm \color{red}{h}} )^2+ (y-{\rm \color{blue}{k}} )^2 = {\rm \color{green}{r}}^2 }\) )))

Answer 10

Got it thanks!

Answer 11

oh you got the equation of the circle? ok then...