Question

Help, will medal =)

Answer 1

To solve this, recall the definition of a perfect square trinomial.

Answer 2

A perfect square trinomial means that the factorized form of the trinomial takes on the form of \[(x-a)^2\]

Answer 3

This means that the roots of the quadratic equation must be repeated.

Answer 4

Now, you just need to plug the coefficients of the given trinomial into the quadratic formula.

Answer 5

\[x = \frac{-b \pm \sqrt{ b^2-4ac }}{ 2a } \]

Answer 6

Notice however, that you have this plus or minus operation in the quadratic formula.

Answer 7

That plus or minus operation is what normally gives you two distinct roots. But you want a repeated root. Your solution is to set the square root term to 0.

Answer 8

so the answer is 0

Answer 9

No, by setting the square root term to 0, I mean:\[b^2-4ac = 0\]

Answer 10

From the problem a = 1, b = -28, c = ?

Answer 11

We are trying to solve for variable c.\[(-28)^2 = 4c\]

Answer 12

Do you understand?

Answer 13

yes so I would just divide (-28)^2 by 4

Answer 14

Correct, and that would be the constant term for your perfect square trinomial

Answer 15

196?

Answer 16

Is 196 correct

Answer 17

Correct