Identify the excluded value for the rational function. y=4x-1 PLEASE help me understand this!!!
this function here, that you posted is a polynomial
that function includes any x-value in it's domain. It is continuous over \((-\infty,~+\infty)\)
there are no excluded x values in a polynomial.
Are you sure because I have already tried answering this and I put 0, and it says that i'm wrong. The options are: 0, 1, 2, and 3.
you put y=4x-1, you see that, correct?
maybe it is \(\large\color{black}{ \displaystyle y=\frac{\rm something}{\rm another~~something } }\)
ya it's y=4/x-1
oh, \(\large\color{black}{ \displaystyle y=\frac{4}{x-1} }\)
that is much better:)
what number can't you divide by, do you know?
x?
4 ÷ what = undefined or indeterminate ?
you can divide by 1, you can divide by 3, you can divide by -0.0003, but you can NOT divide by 0. right?
you can divide by anything, but not by 0
right
so, in your function \(\large\color{black}{ \displaystyle y=\frac{4}{x-1} }\) , there is one x-value that will not give you an adequate output, because you would need to divide by 0.
you are dividing by x-1. so, when (for what x-value) is this the same as dividing by 0 ?
(in other words, when "x-1" is equivalent to 0? when x=what ?)
undefined?
ok, lets go about it in a different way...
you can't divde by 0, you know that?
yes
in our case we are dividing 4 by "x-1", yes?
now, when dividing by x-1, is going to be the same thing as dividing by 0, that will give us an undefined result.
dividing by x-1 is same as dividing by 0, when x-1 is same as 0. there is one x-value for which x-1 is same as 0. x-1=0 when is x-1=0?
idk
I tried my best, I apologize, but I don't think I can help you more. I am capable of you the answer, but I am not going to.
of giving you*
bye
Well thanks anyway
-;( yw
@SolomonZelman I think I am understanding this more. x-1=0 is 1-1=0 is this correct?
So this would mean that the excluded value is 1 right? @SolomonZelman
yes, yes very good!
the excluded value is 1. x≠1
:)
Thank you so much for helping!!
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