Question

HELP PRECALC MEDALS
1.) Find an equation for the nth term of the arithmetic sequence.
a14 = -33, a15 = 9
an = -579 + 42(n + 1)
an = -579 + 42(n - 1)
an = -579 - 42(n + 1)
an = -579 - 42(n - 1)
2. Find an equation for the nth term of the arithmetic sequence.
-15, -6, 3, 12, ...
an = -15 + 9(n + 1)
an = -15 x 9(n - 1)
an = -15 + 9(n + 2)
an = -15 + 9(n - 1)
3. Find an equation for the nth term of the sequence.
-3, -12, -48, -192,
an = 4 • -3n + 1
an = -3 • 4n - 1
an = -3 • 4n
an = 4 • -3n

Answer 1

Kindly separate these questions or tell us what you believe the answer is

Answer 2

(Note: given two point. That can be an exponential function - geometric sequence, or a linear function - arithmetic sequence. However, I conclude from the answer choices that this #1 is arithm. sequence.)

Answer 3

\(\large\color{black}{ \displaystyle a_{14}=-33 }\), \(\large\color{black}{ \displaystyle a_{15}=9 }\)
since we are talking about a geometric sequence
\(\large\color{black}{ \displaystyle {\rm d}=a_{15}-a_{14}=9-(-33)=? }\)

Answer 4

because in geometric sequence, d, the common difference between the terms is
`(a term) - (a term before it)`

so, \(\large\color{black}{ \displaystyle {\rm d}=a_{n-1}-a_{n}={\small(\rm in~this~case)}~~a_{15}-a_{14}=9-(-33)=? }\)

Answer 5

@SolomonZelman an = -579 + 42(n - 1) (?)

Answer 6

@SolomonZelman