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OpenStudy (anonymous):
find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively.
an = 7 (-3)n^( + 1)
an = 7 3^(n - 1)
an = 7 (-3)^(n - 1)
an = 7 3^n
11 years ago
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OpenStudy (anonymous):
@dan815
11 years ago
OpenStudy (anonymous):
\[a _{n}=ar ^{n-1^{}}\]
\[find~a _{2}~and~a _{5}\]
and divide
11 years ago
OpenStudy (anonymous):
let a be the first term
find a2 and a5
11 years ago
OpenStudy (anonymous):
b? @surjithayer
11 years ago
OpenStudy (anonymous):
\[a _{2}=ar ^{2-1}=ar=-21\]
\[a _{5}=ar ^{5-1}=ar^4=567\]
divide
\[\frac{ ar^4 }{ ar }=\frac{ 567 }{ -21 },r^3=-27=\left( -3 \right)^3,r=-3\]
ar=-21
find a
11 years ago
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OpenStudy (anonymous):
can you find?
11 years ago
OpenStudy (anonymous):
\[\frac{ ar }{ r }=\frac{ -21 }{ -3 }=?\]
then write an=?
11 years ago
OpenStudy (solomonzelman):
if 2nd term is negative and 5th term is positive,
then the common ratio is obviously negative.
((There is no other way for such geom. sequence))
11 years ago
OpenStudy (anonymous):
@SolomonZelman its c right?
11 years ago
OpenStudy (solomonzelman):
yes, it's C.
11 years ago
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