Question

Solve the system of equations. 2x-3y+z=-1 3x+2y+2z=-1 x-y-3z=-4

Answer 1

this stuff is a real pain
let the machine do it

Answer 2

you know how?

Answer 3

Not a clue

Answer 4

Which machine?

Answer 5

http://www.wolframalpha.com/input/?i=+2x-3y%2Bz%3D-1%2C+3x%2B2y%2B2z%3D-1%2C+x-y-3z%3D-4

Answer 6

Thank you!

Answer 7

the machine you are typing on

Answer 8

yw

Answer 9

I have another question

Answer 10

The graph of which quadratic equation has a vertex of (-2,1).

Y=(x+1)^2-2
Y=(x-1)^2-2
Y=(x+2)^2+1
Y=(x-2)^2+1

Answer 11

need it by hand (for question 1), then I would suggest matrix. it is already in order for a matrix.

Answer 12

I got the answer to the first question. And I don't know matrix

Answer 13

oh.

Answer 14

`y=(x-h)²+k`

has a vertex (h,k)

Answer 15

now, where would this (h,k) be (-2,1) ? In which of the options?

Answer 16

Y=(x-1)^2+1

Answer 17

y=(x-h)²+k

you need vertex (-2,1)
and in that form the vertex is (h,k)

so h=-2, k=1

y=(x- (-2) )² + (1)
y= ? (you tell me....)

Answer 18

Um I'm not really sure

Answer 19

HI!!

Answer 20

Hello :)

Answer 21

where did your \(-1\) come from?
\[y=(x-\color{blue}h)^2+\color{red}k\] put
\[\color{blue}h=\color{blue}{-2}\] and \[\color{red}k=\color{red}1\]

Answer 22

My bad I meant to put 2 not 1

Answer 23

final answer?

Answer 24

That's what I'm trying to figure out and I can't seem to get it

Answer 25

it is a straight forward substitution
plug in the numbers as above
that is all

Answer 26

So y=(X-2)^2+1?

Answer 27

no dear, the minus sign comes with the number

Answer 28

So y=(x+2)^2+1?

Answer 29

\[y=(x-(-2))^2+1\] but of course you don't want to write \(-(-2)\)

Answer 30

yeah that one has vertex \((-2,1)\)

Answer 31

Thank you! I actually understand it now!

Answer 32

\[\color\magenta\heartsuit\]